A metal cube of edge 12 cm is melted and formed into three smaller cubes if the edges of the two smaller cubes are 6cm and 8cm find the third edge
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cube edge =12cm
area = 6a^2=6×12×12=6864cm^2
the 1st smaller cube area = 6×6×6=216cm^2
the second smaller cube area= 6×8×8=384cm^2
the remaining area =6864-(216+384)=6264
edge of third smaller cube=
Remaining area = 6a^2
6264=6×a^2
6264/6=a^2
a^2=1044
area = 6a^2=6×12×12=6864cm^2
the 1st smaller cube area = 6×6×6=216cm^2
the second smaller cube area= 6×8×8=384cm^2
the remaining area =6864-(216+384)=6264
edge of third smaller cube=
Remaining area = 6a^2
6264=6×a^2
6264/6=a^2
a^2=1044
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