Question

A force F=(6i^-8i^), acts on a particle and displaces it over 4 m along the X-axis
and then displaces it over 6 m along the Y-axis. The total work done during the
two displacements is​

Answer 1

$Work_{x}\\F.d=6*4=24J\\Work_y\\F.d=-8*6=-48j\\Net=24+(-48)=-24 J$

Answer 2

Answer:

-24

Explanation:

W1=F×distance

    =6×4

    =24

W2=F2×d2

     =-8×6

     =-48

∴Wnet=24-48

          -24

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