Question

A force F=i+5j + 7k acts on a particle and
displaces it through S=6i +9k Calculate the
work done if the force is in Newton and distance
is in metre.​

Answer 1

Answer:

69 Jule

Explanation:

F= i+5j+7k

S= 6i+9k

work done= F.S

                 =(i+5j+7k).(6i+9k)

                 =6 i.i + 7*9 k.k                  ( since i.j, i.k, j.i, j.k all are zero )

                 =6+63

                 = 69 Nm

                 = 69 Jule

Answer 2

The work done by the force is 69 Joules.

Explanation:

Given that,

Force, $F=(i+5j + 7k)\ N$

Displacement, $d=(6i +9k)\ m$

We need to find the work done by the force. The work done by an object is given by :

$W=F{\cdot} d$

$W=(i+5j + 7k){\cdot} (6i+9k)$

Using dot product formula, we get :

$W=6+0+63$

W = 69 Joules

So, the work done by the force is 69 Joules. Hence, this is the required solution.

Learn more,

Work done

https://brainly.in/question/7319284