A force F is tangentially applied on the upper surface of a cube of side b and whose lower face is fixed. If modulus of rigidity is η, then upper surface of cube is shifted to
1) F/ηb 2) η/Fb 3) ηb/F 4) Fb/η
Answers
Answered by
43
heyy user ur answer.......
modulus of rigidity is given by
n=force/area/del x/x
del x is shifted on cubes
del x=force×X/area×n
=F×b/b^2×n
del x=F/bn........hope this will help u........@kundan
modulus of rigidity is given by
n=force/area/del x/x
del x is shifted on cubes
del x=force×X/area×n
=F×b/b^2×n
del x=F/bn........hope this will help u........@kundan
Similar questions