Question

A force F = Kxacts on a particle at an angle of
60° with the x-axis. the work done in displacing
the particle from x, to x, will be --
(1) kx?​

Answer 1

Answer:

It could be either kx^2 or 1/2kx^2

Explanation:

the answer would be kx^2 if the displacement is along the force

here, work done = force × displacement along the direction of force

w.d = kx × x = kx^2

or it can be 1/2kx^2 if the displacement is along the horizontal

here, work done = force × displacement × cos theta

w.d = kx × x × 1/2 = 1/2kx^2

or kx^2/2