A force F1 acting on a free mass m at rest produces in it acceleration of 1m/s2. Another force F2 acting on the same mass at rest can produce in it a velocity of 10m/s after 5 s. The greatest acceleration of the mass m when both forces F1 and F2 acts together will be
Answers
Answer:
The greatest acceleration must be 3 ms^-2
Explanation: Here, according to the question ;
For the force F1 , let us consider a free mass (M) = b kg
acceleration (a1)= 1ms^-2
Then , we have the formula from Newtons 2nd law of motion ; i.e. F=ma
So, F1 = M *a1
= b kg* 1ms^-2
= b N
Also, for the force F2 ,
M = b kg (Since second force is also applied for the same mass)
Initial velocity (u) = 0 m/s (Since at first the body is at rest )
Final velocity (v) = 10 m/s
Time (t) = 5 sec.
Then, by formula we can write
F2 = M* a2
= M* [(v-u) /t]
= b * [(10 - 0 ) / 5]
= 2b N
Then, for the greatest acceleration we have to add both the forces i.e.(F1+F2) for the same mass . So,
Greatest acceleration be 'A' and the total force be (F) then,
F1 + F2 = b +2b
F = 3b
M * A = 3b
b * A = 3b
Therefore, A= 3 ms^-2 Ans.
Answer:
Time (t) = 5 seconds.
Explanation:
We have the equation for Newton's second law of motion, F=ma.
So, F1 = M *a1
= b kg* 1ms^-2
= b N
In addition, for the force F2
M = b kg (Since second force is also applied for the same mass) (Since second force is also applied for the same mass)
Initial speed (u) is 0 m/s (Since at first the body is at rest )
Final speed (v) equals 10 m/s
t = 5 seconds.
Next, using a formula, we can write
F2 = M* a2= M* [(v-u) /t]
= b * [(10 - 0 ) / 5]
= 2b N
Then, for the same mass, we must sum both forces, i.e., (F1+F2), to achieve the maximum acceleration. So,
If A is the greatest acceleration and F is the whole force, then
F1 + F2 = b +2b
F = 3b
M * A = 3b
b * A = 3b
As a result, A= 3 ms-2.
Time (t) = 5 seconds.