Question

A force gives an object of m1 and acceleration of 12 metre per second square and an object of mass m2 an acceleration of 10 metre per second square the ratio of acceleration if the force give object of mass m 2 - m1 and m2 plus m1 is

Answer 1

Answer:

30 m/s²  and 8.5 m/s².  

Explanation:

Since we know the value of acceleration for the first object so the mass of that object will be given as m1 = F/12  and the mass of the second object will be m2 = F/10.

Now, the ratio will be, m2/m1 = 12/10.

Therefore the mass difference is m2-m1 = m1*{(12/10)- 1} = 2m1/5=0.4m1.  

For the acceleration of the masses m2-m1 we will get the acceleration of     a2-a1 = 12/0.4 = 30 m/s².  

Now, for the masses m2+m1 the acceleration that we will get is                  a2+a1 = 12/(0.4+1)=12/1.4 = 8.5 m/s².

Answer 2

Answer:

11:1

Explanation:

Given

a1 =12m/s^2 , a2 = 10m/s^2

F1=F2

m1a1 = m2a2

12m1 = 10m2

m1 = 5/6 ×m2

mA = m2- m1

mA = m2 - 5/6×m2

mA = m2/6 --------------(1)

mB = m2+ m1

= m2+5/6×m2

mB = 11m2/6 ---------------(2)

from (1) and (2)

mA×a1 = mB×a2

a1/a2 = mB/mA

11m2/6

= --------------

m2/6

a1/a2 = 11/1

11:1