Question

A force is act on 2 kg mass so that its position as function of time is given by x=3t^2+5 what is the work done by force on mass after 5 sec

Answer 1

Given,X= t^3/3.M= 2kgTime= 2 seconds.Differentiating,X=t^3/3, we get,X=t^2.Putting t=2 in K.E.= 1/2 MV^2, we getK.E= 1/2 X 2X4X4 = 16 NThe answer should be 16 joules