Question

A force is applied at 60° to the horizontal. If the horizontal component of the force is
40 N. Calculate the vertical component?​

Answer 1

Answer:

Let the force be F

Let the force be Fgiven that horizontal component is =40                                  F cos60=40                                         F/2=40                                         F=80now vertical component ,Fsin60=80*√3/2                                              =40√3N

hope it helps you......

please mark me as a brain.....

I WILL FOLLOW YOU.....

Answer 2

Answer:

Nice question mate !!!

Explanation:

Force is resolved in x and y direction

(F)x = F cos(60*)

(F)y = F sin(60*)

From ques, F cos(60*) = 40  

F/2 = 40      F = 80 N

Vertical component = F sin(60*)

                                 = 80 √3/2 = 40√3 N

If u find it as most helpful mark it as Brainliest !!!