Question

A force is applied on a body of mass 20 kg moving with a velocity of 40 m per second

Answer 1

Hope this helps u.....

Answer 2

Let

m1= initial momentum

m2=final momentum

m1=20×40=800kgm/s

m2=20×50=1000kgm/s

F=(m2-m1)/2=100N

Let

a=acceleration=100/20=5m/s^2

now

s=displacement=ut+1/2at^2=

40×1+0.5×5×1=42.5m

W=F×s=4250j