Physics, asked by jagritikaushaloyqvcp, 11 months ago

a force is inclined at 30 degrees to the horizontal.if its rectangular component in the horizontal direction be 50N,find the magnitude of the force and its vertical component

Answers

Answered by garvitpant

3

Fcos30=50
F=100/√3
now Fcos60=x(here x is vertical force)
x=50/√3

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