a force is inclined at 30 degrees to the horizontal.if its rectangular component in the horizontal direction be 50N,find the magnitude of the force and its vertical component
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Fcos30=50
F=100/√3
now Fcos60=x(here x is vertical force)
x=50/√3
F=100/√3
now Fcos60=x(here x is vertical force)
x=50/√3
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