Question

A force is inclined at 60 degree to the horizontal if its rectangular component in the horizontal direction is 50 and then magnitude of the vertical component of force is approximately

Answer 1

Concept Introduction:-

In physics, a pressure is a power which can alternate the movement of an object.

Given Information:-

We have been given that A force is inclined at $60$ degree to the horizontal if its rectangular component in the horizontal direction is $50$.

To Find:-

We have to find that magnitude of the vertical component of force is approximate.

Solution:-

According to the problem

Given that the horizontal component of force is $50$

Force$=60^\circ=50\\F=\frac{50}{cos60^\circ}\\=\frac{50}{\frac{1}{2}}\\=2\times 50\\=100$

$Vertical component=Fsin(60^\circ)\\=100(\frac{\sqrt{3}}{2}\\=50\sqrt{3}$

Final Answer:-

The magnitude of the vertical component of force is approximately is $87$ N.

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Answer 2

Answer:

Expation: break components fx= fcos