Question

a force is inclined to 50 degree to the horizontal. if its rectangular compound is horizontal direction be 50n find the magnitude of force and its vertical component ...

Answer 1

Let the force be F
it is inclined at 50 degree with horizontal.

So F cos50 = 50N
⇒ F = 50/cos50 N
⇒ F = 77.78 N

vertical component, F sin50 = 77.78×sin50 = 59.58 N

Answer 2

Angle =50 degrees

Force = 50 N

So, Fcos50 = 50N

F=77.78N

Vertical component

= Fsin50

=77.78× sin50

=59.58N