Question

A force of 0.5 N is applied on the upper block as shown in figure. The coefficient of static
friction between the two blocks is 0.1 and that between the lower block and the surface is
zero. The work done by the lower block on the upper block for a displacement of 3 m of
the upper block is :-​

Answer 1

Explanation:

f=0.1×0.5=0.05N

net force=0.5-0.05=0.45N

work done= force × displacement=0.45×3=1.35N-m

Answer 2

Explanation:

f=0.1×0.5=0.05N

net force=0.5-0.05=0.45N

work done= force × displacement=0.45×3=1.35N-m