Question

A force of 0.6 N acting on a particle increases it’s velocity from 5ms−1 to 6ms−1in 2s5ms−1 to 6ms−1in 2s . The mass of the particle is pls ans ​

Answer 1

Refer to the Attachment.

Answer 2

Given:

Initial velocity ( u ) = 5 m/s.

Final velocity ( v ) = 6 m/s.

Time taken ( t ) = 2 secs.

Force ( f ) = 0.6 N.

\underline{\bold{Solution :}}

Solution:

We will find the acceleration of the body, using first equation of motion ;

v = u + at

⇒ 6 = 5 + a × 2

⇒ 6 - 5 = 2a

⇒ 2a = 1

⇒ a = 1 / 2

⇒ a = 0.5 m/s².

Now,

Force = mass × acceleration

⇒ Mass = \mathsf {\frac{force}{acceleration} }

acceleration

force

⇒ Mass = \mathsf {\frac{0.6 N}{0.5 m / s{} ^{2} } }

0.5m/s

2

0.6N

⇒ Mass = 1. 2 kg.

Hence, the mass of the particle is 1.2 kg.

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