Question

a force of 0.6N acting on a body increases its velocity from 5m/s to 6m/s in 2s. calculate the mass of the body.

Answer 1

Answer:

$\boxed{\mathfrak{Mass \ of \ the \ body = 1.2 \ kg}}$

Given:

Force (F) = 0.6 N

Initial velocity (u) = 5 m/s

Final velocity (v) = 6 m/s

Time interval (∆t) = 2 s

Explanation:

The rate of change of momentum of a body is directly proportional to the applied force and it takes place in the direction in which the force acts.

$\boxed{ \bold{ \overrightarrow{F} \propto \dfrac{\Delta \overrightarrow{p}}{\Delta t}}}$

m → Mass of body

$\rm \implies \overrightarrow{F} = k \dfrac{\Delta \overrightarrow{p}}{\Delta t} \\ \\ \rm \implies \overrightarrow{F} = k \dfrac{\Delta (m \overrightarrow{v})}{\Delta t} \\ \\ \rm \implies | \overrightarrow{F} | = k \dfrac{m\Delta | \overrightarrow{v} | }{\Delta t} \\ \\ \rm k = 1 : \\ \rm \implies F = \dfrac{m\Delta v }{\Delta t} \\ \\ \rm \implies F = \dfrac{m(u - v) }{\Delta t}$

By substituting values in the equation we get:

$\rm \implies F = \dfrac{m(v- u) }{\Delta t} \\ \\ \rm \implies 0.6 = \dfrac{m(6 - 5)}{2} \\ \\ \rm \implies 0.6 = \dfrac{m}{2} \\ \\ \rm \implies m = 0.6 \times 2 \\ \\ \rm \implies m = 1.2 \: kg$

Answer 2

Given :-

• Force (F) = 0.6 N
• Initial velocity (u) = 5 m/s
• Final velocity (v) = 6 m/s
• Time (t) = 2sec

To Find :-

• The mass of the body.

Solution :-

As we know that,

${ \boxed{ \red{ \bold{a = \frac{v - u}{t} }}}}$

↪ a = 6-5/2

↪ a = 1/2

↪ a = 0.5 m/s²

Now, we know that,

${ \boxed{ \blue{ \bold{F = ma }}}}$

↪0.6 = m × 0.5

↪ m = 0.6/0.5

↪ m = 1.2kg

Hence,

• The mass of the body is 1.2kg.