a force of 1.5N is applied on a object of mass 5kg for 2 sec find the distance covered byobject
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Acceleration would be F/m
1.5/5 = 0.3 m/sec^2
Using kinematics equation
V = u +at
V = 0+ 0.3*2
V = 0.6 m/s
Now V2= U2 + 2as
0.6*0.6 = 0+2*0.3s
0.6*0.6 /0.6 = s
Thus 0.6 m
1.5/5 = 0.3 m/sec^2
Using kinematics equation
V = u +at
V = 0+ 0.3*2
V = 0.6 m/s
Now V2= U2 + 2as
0.6*0.6 = 0+2*0.3s
0.6*0.6 /0.6 = s
Thus 0.6 m
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