Question

A force of 10 N acts on a body of mass 2 kg for 3 seconds, initially at rest. Calculate, i) the velocity acquired by the body and ii) change in momentum of the body. Please don't give links to questions of the same type unless it is to the same question.

Answer 1

Force = mass× acceleration
F =10 N
mass = 2 kg
a = F/m = 10/2 = 5 m/s²
i)now, u = 0
t = 3 sec
v = u + at = 0 + 3×5 = 15 m/s
ii) initial momentum = mu = 2×0 =0
final momentum = mv = 2×15 = 30 kg m/s
change in momentum = final momentum - initial momentum 
                                   = 30 -0 = 30 kg m/s

Answer 2

F=ma

F=10N

Mass=2kg

a=f/m =10/2=5m/s

now,u=0

t=3s

v=u+at=0+3*5=15m/s

Intial momentum=mu=2*0=0

Final momentum=mv=2*15=30km/s

Change in momentum=final momentum- intial momentum=30-0=30kg