Physics, asked by kasakgupta176, 7 months ago

A force of 10 N acts on a body of mass 2 kg for 3s,initially at rest. Calculate: (1) the velocity acquired by the body, and(2) change in momentum of the body.​

Answers

Answered by gourighoshal188
6

Force = Mass × acceleration

F = 10 N

mass = 2kg

a = F/m = 10 /2 = 5m/s²

i) now, u = 0

t = 3 sec

v = u + at = 0 + 3×5 m/s

ii) initial momentum = mu= 2×0=2

final momentum = mv = 2×15 = 30 kg m/s

change of momentum = final momentum - initial momentum

= 30 - 0 = 30 kg m/s

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