Question

A Force Of 10 N Acts On A Body Of Mass 2KG For 3 Seconds , Intially At Rest .
Calculate :
( i ) The Velocity Acquired By The Body
( ii ) Change In Momentum Of Body
Solve in detail

Answer 1

Answer:

V = 15 m/s                  &     ΔP = 30 Ns

Explanation:                                

Given data

F = 10 N

m = 2 Kg

t = 3 s

(i) V = ?   (ii) ΔP = ?

Solution:

(i) F = ΔP / Δt                        ≡   (ii)  F = ΔP / Δt                        

  F = Δ(mV) / Δt                     ≡       ΔP = F Δt

   10 = 2 V / 3⇒V = 30 / 2    ≡      ΔP = 10(3)

    V = 15 m/s                        ≡     ΔP = 30 Ns

Answer 2

From Newton's second law, F = ma. Or, a = F/m = 10/2 = 5 ms-2.