Question

A force of 10 N is requrid to draw rectangular glass plate on the surface of a liquid with some velocity. Force needed to draw another glass plate of 3 times length and 2 times width is

Answer 1

Answer:

Given,

$10n(lb) \frac{dv}{dy} = 1$

Now, Area of new plate= 3l×2b=6Lb

$so \: force \: = n \: 6lb \frac{dv}{dy} = 6(n \: lb \frac{dv}{dy} \: (from \: 1)$

=60N