Question

a force of 10 Newton is acting on a body at an angle of 60 degree with the horizontal displaces the body for distance of 2 metre calculate the work done by the force makes the angle 30 degree with the horizontal what is the value of Force 2 display see the body through 2 metre so that the work done is 10 joule​

Answer 1

Answer:

The angle is measured in degrees and you have provided it as 600. Which obviously means 60 since the superscript to signify degree was written as ‘0’ in your question.

Force, F = 10 N

Angle with horizontal, θ = 60°

Displacement in horizontal direction, S = 2 m

Component of force along horizontal direction is = F cosθ =(10)(cos60) =5 N 

So, work done is, W = (5)(2) = 10 J

Second case: 

Force, F = ? 

Angle with horizontal, θ = 30°

Displacement in horizontal direction, S = 2 m

Component of force along horizontal direction is=Fcosθ=(F)(cos30)=F(√3/2)                                                                                                                N

Any non­zero value of force will cause a displacement of 2 m.

Answer 2

Answer:

Force=10N

direction=cos60d

work done=10*cos60d

=10*1/2

=5N

so work is 5N*2

=10joule