Question

A force of 100 N acts upon a stationary body of mass 25KG for 5 sec .What velocity does it generate ?
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[BOARD] CBSE
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No Spmming ​

Answer 1

$\Large\bold{\underline{\underline{Answer:-}}}$

$\huge{20\:m/s}$

$\bf\small\bold{\underline{\underline{Step-By-Step\:Explanation:-}}}$

As we know

$\sf\Large\boxed{F =ma}$

Here Given F = 100 N, m = 25 kg

Putting in the equation

$\sf\Large{100=25\times\:a}$

On solving

$\sf\Large{\Rightarrow\:a = 4 \:ms^{-2} }$

Now the body initially is stationary therefore initial velocity (u) must be zero

u = 0

Applying Newton 1st Law of Motion :

$\sf\Large\boxed{v =u + at}$

Substituting the values to find final velocity at t= 5 sec

$\sf\bold{v = 0 + 4 \times \:5}$

$\bf\bold{\Rightarrow\:v = 20 \:m/s}$

Hence, the final velocity is 20 m/s

Answer 2

Solution:

From the Question,

• Force applied,F = 100 N

• Mass of the object;m = 25Kg

• Force is applied on the object for a time interval of 5s

As the object is said to be stationary,it's initial velocity is zero »u=0m/s

•Using the formula F = ma,

a = F/m

→a = 100/25

→a = 4m/s²

•Using the relation v = u + at,

v = (0) + (4)(5)

→v = 20m/s

• The velocity of the object is 20m/s