a force of 1000 N acts on a particle a force of 1000 Newton acts on a particle parallel to its direction of motion with is horizontal. Its velocity increases from 1 m/s to 10m/s, when the force act through a distance of 4 metre. calculate the mass of particle. Given a force of 10 N is necessary for overcoming friction
Answers
So,
If we equate the force we would arrive at the equation,
F - F(friction) = ma
F= 1000N
F(friction) = 10N
Now,
1000 - 10 =ma
990 = ma
Now,
To find the value of a we use the principles of kinematics,
We know that,
v² = u² +2as
10² = 1² +2×a×4
100 - 1 = 2×a×4
8a = 99
a= 99/8
Substituting in the above equation,
990 = m × (99/8)
m= 10× 8
m= 80kg
SO,
The mass of the object is 80 kg
Given force = 1000N.
Given that force of 10N is necessary for overcoming friction.
F = 1000 - 10
= 990 N.
Given its velocity increases from 1 m/s to 10 m/s through distance of 4 m.
Here, Initial velocity u = 1, Final velocity v = 10, S = 4 m.
We know that v^2 - u^2 = 2as.
= > 10^2 - 1^2 = 2 * a * 4
= > 100 - 1 = 8a
= > 99 = 8a
= > a = 99/8.
Now,
We have a = 99/8, F = 990, m = ?
We know that F = ma.
= > 990 = m * (99/8)
= > 990 * 8 = 99m
= > 7920 = 99m
= > m = 7920/99
= > m = 80kg.
Therefore, the mass of the particle = 80kg.
Hope this helps!