Question

A force of 100n is applied on a block of mass 3kg the coefficient of friction is 1/√3.the friction force acting on block is

Answer 1

Answer is
$17.32$

Answer 2

Frictional force = ωmg

Where ω = the coefficient of friction.

m = mass

g = acceleration due to gravity.

Now :

g = 10

m = 3kg

ω = 1/√3

Doing the substitution :

F = 10 × 3 × 1/√3

= 30/√3 N