A force of 10N act on a body of mass 2kg for 3s initially at rest. Calculate
(i)Velocity acquired by body.
(ii)Change in moment of body.
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Your answer
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Force = F = 10 N
Mass = m = 2 kg
Time = t = 3 s
Initial velocity = 0 m/s
(I) Velocity acquired by the body (v)
F = ma
=> F = m × (v - u )/t
=> 10 = 2 × (v - 0)/3
=> 10 = 2 × v/3
=> v = (10 × 3)/2
=> v = 15 m/s
(ii) Change in momentum
Change in momentum = P2 - P1
= mv - mu
= m(v - u)
= 2( 15 - 0) kg m/s
= (2 × 15 ) kg m/s
= 30 kg m/s
HOPE IT HELPS
---------------
Your answer
---------------------
Force = F = 10 N
Mass = m = 2 kg
Time = t = 3 s
Initial velocity = 0 m/s
(I) Velocity acquired by the body (v)
F = ma
=> F = m × (v - u )/t
=> 10 = 2 × (v - 0)/3
=> 10 = 2 × v/3
=> v = (10 × 3)/2
=> v = 15 m/s
(ii) Change in momentum
Change in momentum = P2 - P1
= mv - mu
= m(v - u)
= 2( 15 - 0) kg m/s
= (2 × 15 ) kg m/s
= 30 kg m/s
HOPE IT HELPS
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