The sum of length, breadth and height of a cubiod is 38 cm and the length of its diagonal is 22cm. Find the total surface area of the cuboid
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1
L + b + h = 38 cm
also diagonal = 22 cm
so root over < l2 + b2 + h2> = 22
l2 + b2 + h2 = 484
(l + b + h)2 - 2lb -2bh -2hl = 484
(38)2 - ( 2lb + 2bh + 2hl) = 484
- ( 2lb + 2bh + 2hl) = 484 - 1444
- ( 2lb + 2bh + 2hl) = - 960
( 2lb + 2bh + 2hl) = 960
so TSA = 960 cm2
also diagonal = 22 cm
so root over < l2 + b2 + h2> = 22
l2 + b2 + h2 = 484
(l + b + h)2 - 2lb -2bh -2hl = 484
(38)2 - ( 2lb + 2bh + 2hl) = 484
- ( 2lb + 2bh + 2hl) = 484 - 1444
- ( 2lb + 2bh + 2hl) = - 960
( 2lb + 2bh + 2hl) = 960
so TSA = 960 cm2
Answered by
3
here..........
The surface area of cuboid is
960sq.cm
The solution to it is givenin the pic.
hope this helps ! ! !#
The surface area of cuboid is
960sq.cm
The solution to it is givenin the pic.
hope this helps ! ! !#
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