Question

A force of 10N acting on a body at an angle of 60 deg. with the horizontal direction displaces the body through a distance of 2m along the surface of a floor. Calculate the work done.

Now let the force or pulling act on the body makes an angle of 30 deg. with the horizontal. What is the value of the force to displace the body through 2m along the surface of the floor? (Cos 60 =1/2. and Cos 30 = √3/2) w = F S cos Q

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Answer 1

Answer:

work done = force * displacement (cosø)

work done = 10 * 2 cos60°

cos60°=1/2

so,

work done = 10*2*1/2=10J

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Answer 2

Answer:

Explanation:

1) formula :-

W = F*S*cos theta

so,

Work done = 10 * 2 * 1/2

W = 10 J.

2)

10 = F * 2 * root 3/2

10^2 = 3 * F

100/3 = F

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