Question

A force of 10N acts for 20 seconds on a body of mass 2kg initially at rest. calculate the energy required by the body and the workdone by the applied force.​

Answer 1

Explanation:

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Answer 2

Work Done= 10,000 joule or 10 KJ

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Given:-

Force = 10N

time = 20sec

Mass of body = 2kg

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Solution:-

• F = ma
• F = m x (v-u)/t
• Ft = mv - mu
• 10x20 2(v) - m(0)
• 200/2 = v
• 100m/s = v

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KE = Work Done

1/2 × m × v² - 1/2 × m × u² = W

1/2 × (2) × (100)² - 1/2 × (2) × (0)² = W

10000 - 0 = W

10000J = W

10kJ = W

W = 10kJ

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