Question

a force of 10n acts on a body of mass 20 kg for 10 seconds. the change in its momenentum is​

Answer 1

Answer:

50 kgm/s

Explanation:

f=10 N

m=20 kg

t=10 s

$a = \frac{f}{m} \\ a = \frac{10}{20} \\ a = \frac{1}{2}$

v=u+at

$v = 0 + \frac{1}{2} \times 10 \\ v = 5 \: \frac{m}{s}$

M(Momentum)=mv

$momen = 10 \times 5 \\ momen = 50 \: \frac{kgm}{s}$

Momentum = 50 kgm/s