Question

a force of 10n acts on a body of mass 2kg moving initially with a velocity of 4m/s. find the velocity attained by the body in 5 sec​

Answer 1

Answer:

• The velocity attained by the body in 5 sec is 29 m/s.

Explanation:

Given that,

• Force (F) = 10 N
• Mass (m) = 2 kg
• Initial velocity (u) = 4 m/s
• Time (t) = 5 sec

As we know that,

Force = mass × acceleration

[ Putting values ]

➡ 10 = 2 × a

➡ a = 10/2

➡ a = 5 m/s²

❤ Applying 1st eqn. of motion, ❤

v = u + at

[ Putting values ]

➡ v = 4 + 5 × 5

➡ v = 4 + 25

➡ v = 29 m/s

$\red\bigstar$ Velocity = 29 m/s $\green\bigstar$

Answer 2

★ Newton's Second Law :

★ Force (F) : It is defined as a force in which a mass moves with some acceleration . In mathematically it is written as ,

➳ F = m × a

➳ SI units : Newton

★ Acceleration (a) : It is defined as rate of change in velocity .

➳ a = (v - u) / t

➳ SI units : m/s²

_________________________________

Force acts on a body (F) = 10 N

Mass of the body (m) = 2 kg

Initial velocity of the body (u) = 4 m/s

Final velocity of the body (v) = ? m/s

Time taken (t) = 5 s

➠ F = ma

➠ 10 = 2(a)

➠ 10 = 2 × $\sf \bigg(\dfrac{v-u}{t}\bigg)$

➠ 5 = $\sf \dfrac{v-4}{5}$

➠ 25 = v - 4

➠ v = 25 + 4

➠ v = 29 m/s  $\orange{\bigstar}$