Question

A force of 10N displace a body by 6m in 3 sec the power of the agency applying the force is

Answer 1

Power=force*displacement/time
So, force=10N
Displacement=6m
Time=3s
Then,power=10*6/3=20w

Answer 2

Answer:

Power of the agency applying the force is 20Watt

Explanation:

Given force applied,  $F=10N$

         displacement a body, $s=6m$

          time, $t= 3 sec$

Power is defined as work done in unit time, i.e.,

                       $P=\frac{Work }{time} =\frac{Force\times displacement}{time}$

                                        $=\frac{10\times 6}{3}=20W$

Therefore, power of the agency applying the force is 20Watt