Question

A force of 120 N acts on the surface of area 4 square meter normally. What would be the pressure on the surface?

Answer 1

Given,

Force(F) = 1200 N

Area (A) = 10 cm² = 0.001 m²

We know,

Thrust is the force acting normally to a surface.

So, Thrust = 1200 N

And, Pressure = Thrust / Area

                       = 1200 / 0.001

                      = 1200000 Pa

                      = 1.2 × 10⁶ Pa

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