Question

A force of 1200N acts on the surface of area 10cm 2 normally.What would be the thrust and pressure on the surface?​

Answer 1

Force, F = 1200 N

Area = 10 cm² or 10/10000 or 10^-3 m²

Pressure ( Thrust ) = Force / Area

==> 1200 / 10^-3

==> 12×10² / 10^-3

==> 12 × 10^5 Pascal

Answer 2

Answer:

P = 1.2 × 10⁶ Pa

Explanation:

Given :

Force F = 1200 N

Area A = 10 cm² = 10 × 10⁻⁴ m²

We are asked to find thrust and pressure :

Since thrust is perpendicular force :

Thrust = 1200 N

Now we know :

Pressure = Force / Area

P = F / A

Putting values here we get :

= > P = 1200 / 10 × 10⁻⁴  Pa

= >  P = 120 /  10⁻⁴  Pa

= >  P = 120 × 10⁴ Pa

= > P = 1.2 × 10⁶ Pa

Hence we get required answer!