Physics, asked by azadkachroo1981, 1 year ago

A force of 1200N acts on the surface of area 10cm square normally. What would be the thrust and pressure on the surface

Answers

Answered by luciferxixo
5


Since Pressure = Force / Area
P = 1200 x 10 / 1
P = 12000 Pascal

I hope this answer helped you.
Answered by duragpalsingh
2

Hey there!

Given,

Force(F) = 1200 N

Area (A) = 10 cm² = 0.001 m²

We know,

Thrust is the force acting normally to a surface.

So, Thrust = 1200 N

And, Pressure = Thrust / Area

                        = 1200 / 0.001

                       = 1200000 Pa

                       = 1.2 × 10⁶ Pa

Hope it Helps You!

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