A force of 150n is given on a piston of area of cross section 12cm2 in the hydraulic machine neglecting friction , find the force that is to be applied on a piston of area of cross selection 2cm2.
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Explanation:
We know that in a hydraulic machine, Pressure in equal on both sides.
Pressure on narrow piston = Pressure on wider piston
∴ P
1
= P
2
∴
A
1
F
1
=
A
2
F
2
∴
2×10
−4
F
1
=
12×10
−4
150
∴ F
1
= 25 Newton
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