A force of 15n acts for 5s on a body of mass 5kg which is initially at rest .Calculate: a] final velocity of the body b] the displacement of the body
Answers
Answered by
91
F=ma
=>a=F/m=15/5=3m/s²
using equation v=u₊at
v=0+3(5)=15m/s
using equation
(15)²-0=2(3)(s)
=>s=(15)²/6=37.5m
=>a=F/m=15/5=3m/s²
using equation v=u₊at
v=0+3(5)=15m/s
using equation
(15)²-0=2(3)(s)
=>s=(15)²/6=37.5m
Answered by
43
F=ma
=>a=F/m=15/5=3m/s²
using equation v=u₊at
v=0+3(5)=15m/s
using equation v^{2}-u^{2} =2as
(15)²-0=2(3)(s)
=>s=(15)²/6=37.5m
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