Science, asked by annysurDesyeda, 1 year ago

A force of 15n acts for 5s on a body of mass 5kg which is initially at rest .Calculate: a] final velocity of the body b] the displacement of the body

Answers

Answered by animeshkumar48
91
F=ma
=>a=F/m=15/5=3m/s²

using equation v=u₊at
v=0+3(5)=15m/s

using equation  v^{2}-u^{2} =2as
(15)²-0=2(3)(s)
=>s=(15)²/6=37.5m
Answered by devangvyawahare10
43

F=ma  

=>a=F/m=15/5=3m/s²

using equation v=u₊at

v=0+3(5)=15m/s

using equation  v^{2}-u^{2} =2as

(15)²-0=2(3)(s)

=>s=(15)²/6=37.5m

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