Science, asked by gamerepicboy, 1 day ago

a force of 1700N is applied to a 1300kg car.What is the magnitude of acceleration of the car?

Answers

Answered by shrutikshajadhav

0

Answer:

Correct option is

C

20 N downwards

Net force in upward direction fa=Fsin30−mg

=100×21−3×10=20N

Limiting friction Fl=μFcos30o

=41×10023=21.15N

Hence block will not slip. Hence

fr=fa=20N

Explanation:

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