a force of 2.25N acts on a charge of 15 × 10^-4C the intensity of electric field at that point is
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E or intensity of electric field is given by
F/q
So,
E = 2.25/(15*10^-4)
= 22500/15
= 1500 N/C
F/q
So,
E = 2.25/(15*10^-4)
= 22500/15
= 1500 N/C
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