A force of 20 N displays a body through a distance of 1 m at an angle of 60° from its own direction. Calculate the amount of work done.
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Given
Force (F) = 20 N
Displacement (s) = 1 m
Angle between force and displacement θ = 60°
★ Work (W) = Fs cos θ
= 20 × 1 × cos 60°
= 20 × 1 × ½
= 10 J
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hey mate!!
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A force of 20 N displaces a body through a distance of 1 mat an angle of 60° from its own direction. Calculate the amount of work done.
A force of 20 N displaces a body through a distance of 1 mat an angle of 60° from its own direction. Calculate the amount of work done.Here, force F = 20 N, displacement, s = 1 m.
A force of 20 N displaces a body through a distance of 1 mat an angle of 60° from its own direction. Calculate the amount of work done.Here, force F = 20 N, displacement, s = 1 m.Angle between force and displacement 0 60°.
A force of 20 N displaces a body through a distance of 1 mat an angle of 60° from its own direction. Calculate the amount of work done.Here, force F = 20 N, displacement, s = 1 m.Angle between force and displacement 0 60°.Workdone,W =Fscos0 =20 X 1 X cos60°=20X 1 X 1/2 = 10J.
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