Question

A force of 20 N displays a body through a distance of 1 m at an angle of 60° from its own direction. Calculate the amount of work done.​

Answer 1

Given

Force (F) = 20 N

Displacement (s) = 1 m

Angle between force and displacement θ = 60°

★ Work (W) = Fs cos θ

= 20 × 1 × cos 60°

= 20 × 1 × ½

= 10 J

Answer 2

force = 20 N

distance = 1 m

theta = 60 degrees

work done = FS cos theta

= 20 * 1 * cos 60

= 20 * 1/2

= 10 Nm