A FORCE OF 200 N ACTS UPON A BODY OF MASS 50 KG AT REST. FIND THE WORK DONE IN 10 SECOND.
Answers
Answered by
0
Explanation:
acceleration of a body 200/50 is 4 m/sec.sec
displacement in 10 sec is S
S =ut+1/2at^2
S=1/2(4)(100) ......u=o for initially rest body
=200 meters
work = 200×200
=40000 Joules
Similar questions