Physics, asked by saujanyashukla31, 6 months ago

A FORCE OF 200 N ACTS UPON A BODY OF MASS 50 KG AT REST. FIND THE WORK DONE IN 10 SECOND.

Answers

Answered by surya77287

0

Explanation:

acceleration of a body 200/50 is 4 m/sec.sec

displacement in 10 sec is S

S =ut+1/2at^2

S=1/2(4)(100) ......u=o for initially rest body

=200 meters

work = 200×200

=40000 Joules

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