Question

a force of 200 N acts upon a half kg object for 10 seconds if the object was moving at a speed of 1 metre per second before the force was applied calculated the speed after the force

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Answer 1

Answer:

$\huge \red{4001\: m {s}^{ - 1} }$

Explanation:

First calculate acceleration of objects

$f = ma \\ \\ \implies \: a = \frac{f}{m} = \frac{200}{ \frac{1}{2} } \\ \\ \implies \: a = 400 \: \frac{m}{ {s}^{2} }$

Now first equation of motion

$v = u + at \\ \\ \implies \: v = 1 + 400 \times 10 \\ \\ \implies \: v = 4001 \: m {s}^{ - 1}$

Answer 2

Answer:

Given :-

• A force of 200 N acts upon a half kg object for 10 seconds.
• The object was moving at a speed of 1 m/s before the force was applied.

To Find :-

• What is the speed or final velocity.

Formula Used :-

$\bigstar$ Force Formula :

$\mapsto \sf\boxed{\bold{\pink{F =\: ma}}}$

where,

• F = Force
• m = Mass
• a = Acceleration

$\bigstar$ First Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v =\: u + at}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Solution :-

First, we have to find the acceleration of an object :

Given :

• Force = 200 N
• Mass = 1/2 Kg

According to the question by using the formula we get,

$\implies \sf 200 =\: \dfrac{1}{2} \times a$

$\implies \sf 200 =\: \dfrac{a}{2}$

By doing cross multiplication we get,

$\implies \sf a =\: 200(2)$

$\implies \sf\bold{\purple{a =\: 400\: m/s^2}}$

Now, we have to find the speed or final velocity :

Given :

• Initial Velocity = 1 m/s
• Time = 10 seconds
• Acceleration = 400 m/s²

According to the question by using the formula we get,

$\implies \sf v =\: 1 + 400(10)$

$\implies \sf v =\: 1 + 400 \times 10$

$\implies \sf v =\: 1 + 4000$

$\implies \sf\bold{\red{v =\: 4001\: m/s}}$

$\therefore$ The speed after the force is 4001 m/s .

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EXTRA INFORMATION

✭ Equation Of Motion :

➵ First Equation Of Motion :

$\mapsto \sf\bold{\green{v =\: u + at}}$

➵ Second Equation Of Motion :

$\mapsto \sf\bold{\red{s =\: ut + \dfrac{1}{2}at^2}}$

➵ Third Equation Of Motion :

$\mapsto \sf\bold{\purple{v^2 =\: u^2 + 2as}}$

where,

• s = Distance Covered or Distance Travelled
• u = Initial Velocity
• v = Final Velocity
• a = Acceleration
• t = Time Taken