Question

a force of 200 N acts upon a half kg object for 10 seconds if the object was moving at a speed of 1 metre per second before the force was applied calculated the speed after the force iska ans de do ​

Answer 1

Answer:

4001ms

−1

Explanation:

First calculate acceleration of objects

\begin{gathered}f = ma \\ \\ \implies \: a = \frac{f}{m} = \frac{200}{ \frac{1}{2} } \\ \\ \implies \: a = 400 \: \frac{m}{ {s}^{2} } \end{gathered}

f=ma

⟹a=

m

f

=

2

1

200

⟹a=400

s

2

m

Now first equation of motion

\begin{gathered}v = u + at \\ \\ \implies \: v = 1 + 400 \times 10 \\ \\ \implies \: v = 4001 \: m {s}^{ - 1} \end{gathered}

v=u+at

⟹v=1+400×10

⟹v=4001ms

−1