Question

a force of 200N avts for 0.8sec on a body of mass 6.4kg which is initially at rest. the velocity attained by the body is​

Answer 1

Answer:

25 m/s

Explanation:

Given:

Force (F) = 200 N

Time (t) = 0.8 seconds

Mass (m) = 6.4 kg

Initial velocity (u) = 0 m/s (Since the body was at rest)

To find:

Final velocity (v)

Formula:

To find the final velocity, we first need to find the acceleration.

F = ma

⇒ 200 = 6.4 * a

⇒ a = 200/6.4 = 31.25 m/s²

v = u + at

⇒ v = 0 + (31.25 * 0.8)

⇒ v = 25 m/s

Hence, the velocity attained by the body is 25 m/s.