A force of 20N acts on a body of mass 5kg at rest. What is the acceleration of the body? What is its velocity after 5s if the same force acts?After 5s the force ceases to açt how will the body move?
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Answered by
7
f=ma
a= f/m =20÷5 = 4m/sec^2
a= f/m =20÷5 = 4m/sec^2
Answered by
11
a=f/m = 20/5= 4m/s^2
now initial velocity is 0 m/s
using first eq of motion
v= u + at
v= 0 + 4×5
v= 20m/s.
now s= ut + 1/2 at^2
s= 0+ 4×5×5/2
s= 50 m
body will move 50 m
now initial velocity is 0 m/s
using first eq of motion
v= u + at
v= 0 + 4×5
v= 20m/s.
now s= ut + 1/2 at^2
s= 0+ 4×5×5/2
s= 50 m
body will move 50 m
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