Question

A force of 20N acts on a particle of mass 2 kg and displaces it by 5m at an angle 30°. What is the work done?​

Answer 1

we know

W = f.s

⏩

$w = f \ \: scos( \alpha )$

$= 20 \times 5 \times \frac{ \sqrt{3} }{2}$

$= 50 \sqrt{3}$

⏩ I hope it help you ❤️

Answer 2

The work done by the object is 50√3Nm.

Given:-

Force (f) = 20N

Mass (m) = 2kg

Displacement (s) = 5m

Angle (a) = 30°

To Find:-

The work done by the object.

Solution:-

We can easily calculate the work done by the object by using the following procedure.

As

Force (f) = 20N

Mass (m) = 2kg

Displacement (s) = 5m

Angle (a) = 30°

According to the formula of the Work,

$w = f \times s \times \cos(a)$

there is no requirement of mass in this formula.

So,

$w = 20 \times 5 \times \cos(30)$

$w = 100 \times \frac{ \sqrt{3} }{2}$

$w = 50 \sqrt{3}$

Hence, The work done by the object is 50√3Nm.

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