Question

A force of (2500+-5) is applied over an area of (0.32+-0.02) m2. calculate the error in the measurement of pressure.​

Answer 1

Answer:

pressure=force/area=2500/0.32

=7812.5 N/m^2

∆p/p =∆F/F+∆A/A

=(5/2500+0.02/0.32) =.0645

∆P =.0645*7812.5

∆P=503.9 N/m^2

pressure required

=(7812.5+503.9) N/m^2.

hope it helps you