Question

a force of 30 new ton acts on a mass of 12 kg at rest for 10 seconds . find the final velocity of the body after 10 seconds

Answer 1

Answer:

• The Final velocity (v) is 25 m/s

Given:

1. Force Applied (F) = 30 N
2. Mass (M) = 12 Kg
3. Time taken (t) = 10 seconds.
4. Initial velocity (u) = 0 m/s

Explanation:

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From Newton's Second law of motion,

⇒ F = M a

Where,

• F Denotes Force Applied
• M Denotes Mass.
• a Denotes Acceleration.

Substituting the values,

⇒ 30 N = 12 Kg × a

⇒ 30 = 12 × a

⇒ 30 / 12 = a

⇒ a = 30 / 12

⇒ a = 2.5

⇒ a = 2.5 m/s²

∴ We got the acceleration.

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Applying first Kinematic Equation, we know,

⇒ v = u + a t

Where,

• v Denotes Final velocity.
• u Denotes initial velocity.
• a Denotes acceleration.
• t Denotes time taken.

Substituting the values,

⇒ v = 0 + ( 2.5 × 10 )

⇒ v = ( 2.5 × 10 )

⇒ v = 25

⇒ v = 25 m/s

∴ The Final velocity (v) is 25 m/s.

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Answer 2

ANSWER:

Given

• Force of 30N acting on a body of mass 12kg . At rest for 10s

TO FIND:

Final velocity (v) after 10s

SOLUTION:

Using

★ Force = Mass × Acceleration

Substituting we get

→ 30N = 12 × a

→ 30/12 = a

→ 5/2 = a

→ Acceleration ( a ) = 2.5 m/s²

Using

★ v = u + at

Where,

• v = Final velocity = ?
• u = Initial velocity = 0 m/s
• a = Acceleration = 2.5m/s²
• t = Time = 10s

Substituting we get

➻ v = 0 + (2.5)(10)

➻ v = 25m/s

Hence, final velocity ( v ) = 25m/s