Question

A force of 30 Newton inclined at an angle theta to the horizontal if its vertical component is 18 Newton find the horizontal component and the value of theta

Answer 1

Answer:

30² = 18² + x²

x² = 576

x = 24N

Tanθ = 18/24 = 3/4

θ = 37°

Horizontal component = 24N

Value of θ = 37°xplanation:

Answer 2

Concept:

• Forces
• Vectors
• Splitting a vector into its horizontal and vertical components

Given:

• Force = 30N
• Force is inclined at an angle θ
• The vertical component of the force = 18N

Find:

• The horizontal component of the force
• The value of the angle θ

Solution:

The vertical component of the force = F sin θ

The vertical component of the force = 18

F sin θ = 18

F = 30

30 sin θ = 18

sin θ = 18/30 = 3/5

θ = 37°

The horizontal component of the force = F cos θ

The horizontal component of the force = 30 cos 37° = 24

The horizontal component of the force is 24N.

The value of theta is 37°

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